Learning Task No.2:perform The Indicated Operation
learning task no.2:perform the indicated operation
Answer:
1.
[tex]\frac{2x}{x-1}+\frac{x}{x-1}=\frac{2x+x}{x-1}=\boxed{\frac{3x}{x-1}}[/tex]
2.
[tex]\frac{4x+1}{x+6}-\frac{2x-8}{x+6}=\frac{4x+1-(2x-8)}{x+6}=\frac{4x+1-2x+8}{x+6}=\frac{4x-2x+1+8}{x+6}=\boxed{\frac{2x+9}{x+6}}[/tex]
3.
[tex](\frac{y^2-y-2}{5y})(\frac{10y}{y+1})=\frac{10y(y^2-y-2)}{5y(y+1)}=\frac{10y(y-2)(y+1)}{5y(y+1)}=2(y-2)=\boxed{2y-4}[/tex]
[tex]\frac{y+1}{y+1}[/tex] is equal to 1; [tex]\frac{10y}{5y}[/tex] is equal to 2.
4.
[tex]\frac{6}{28x+4}[/tex] ÷ [tex]\frac{6}{35x+5}=\frac{6}{28x+4}*\frac{35x+5}{6}=\frac{6(35x+5)}{6(28x+4)}=\frac{6(5)(7x+1)}{6(4)(7x+1)}=\boxed{\frac{5}{4}}[/tex]
[tex]\frac{6}{6}[/tex] is equal to 1; [tex]\frac{7x+1}{7x+1}[/tex] is equal to 1.
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